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Question: Infinite grid of resistors with resistance R, find resistance between two adjacent points



uh for this question I don't get it why you have the other nodes carrying 1 + 1 + 1 - (2α+β) amperes. Shouldn't it just be 3A as stated in the diagram?

Also, considering that after superposing the two circuits you have a total of 8A in the circuit, why is this
which arrives from considering voltages wrong?


Also if someone can come up with an alternative explanation for how you would solve this using superposition that would help, thanks <3

Just use vectors bro

Scris de boywind2, 16.09.2018 at 01:31

Just use vectors bro

Everyone who read Bjarne Stroustrup book would laugh his ass right now

Also Luke I wish I could help you but I am a fool. You will have to wait for Pavle/WD or ask a teacher

Https://www.mathpages.com/home/kmath668/kmath668.htm

THANOS CAR du du dududu

Scris de smegma lover, 16.09.2018 at 03:17

Https://www.mathpages.com/home/kmath668/kmath668.htm

I got my screenshot from there -_-

I am in bus currently, could not write a lot, and it is very bad written, sry.
Anyways, when you "attach" exact node A to the infinite powersource, that power will part in 4 ways, equally.
If you attach "infinite negative charge", and turn off the other powersource, you would get four ways of getting power, equally.
(all imagination etc)
This means that between those two, it is easily just 2 times 1/4 = 1/2.
When power continue though the next node, the total amount of power that enters will exit the node. But now, it wont go like it did in first node, different power wil go through left and right node and next node, that is why 2A + B = 1, and not 3A.

Scris de Oleg, 16.09.2018 at 05:08

didnt realize so much mathmatics went into red stones in minecraft...

Scris de LukeTan, 16.09.2018 at 04:57

Scris de smegma lover, 16.09.2018 at 03:17

Https://www.mathpages.com/home/kmath668/kmath668.htm

I got my screenshot from there -_-

ye ik

Scris de 4nic, 16.09.2018 at 03:40

THANOS CAR du du dududu